mySQL query solution
Submitted by lishevita on Tue, 07/22/2008 - 12:55
category:
I had been trying very hard to avoid having to do a nested query, but in the end, I really couldn't figure out a way around it. This is the query that gets the job done:
If you have a non-nested solution for this problem, I'd still love to see it!
mysql> select tnid from fr_strings where sid NOT IN (SELECT sid from fr_tr_by_uid where uid = 1 and language = 'es');
If you have a non-nested solution for this problem, I'd still love to see it!